Asked by Justin
Solve each equation by factoring:
(2x+1)(3x-2)=10
How do you get -4/3 and 3/2 out of this equation? I'm so confused
(2x+1)(3x-2)=10
How do you get -4/3 and 3/2 out of this equation? I'm so confused
Answers
Answered by
Reiny
You can only use the factors if the right side of the equation is 0
Yours is not, so expand and simplify first
6x^2 - 4x + 3x - 2 = 10
6x^2 - x - 12 = 0
now factor it
(3x+4)(2x-3) = 0
then 3x+4 = 0 or 2x-3 = 0
x = -4/3 or x = 3/2
Yours is not, so expand and simplify first
6x^2 - 4x + 3x - 2 = 10
6x^2 - x - 12 = 0
now factor it
(3x+4)(2x-3) = 0
then 3x+4 = 0 or 2x-3 = 0
x = -4/3 or x = 3/2
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