Question

On a coordinate plane, a line goes through (0, negative 4) and (12, 6). A point is at (12, negative 2).
What is the equation of the line that is parallel to the given line and passes through the point (12, −2)?

y = –Six-fifths x + 10
y = –Six-fifths x + 12
y = –Five-sixths x – 10
y = Five-sixths x – 12

Answer 1

Slope = (6−(−4))/(12−0) = 10/12 = 5/6.
Use y = (5/6)x + b with (12, −2): −2 = (5/6)(12) + b = 10 + b ⇒ b = −12.

Answer: y = (5/6)x − 12 (the last choice).