Asked by Anonymous
A flaming arrow is shot into the air to mark the beginning of the a festival. Its height, h, in meters after t seconds can be modelled by the function h(t)=-4.9t^2+24.5t+2
How fast is the arrow traveling when it hits the ground? Explain how you arrived at your answer.
(prior to that i found the time it takes for the arrow to reach the ground level a 5.0803s)
How fast is the arrow traveling when it hits the ground? Explain how you arrived at your answer.
(prior to that i found the time it takes for the arrow to reach the ground level a 5.0803s)
Answers
Answered by
drwls
The way to solve this is explained in your subject title. Compute the derivative of the function, which is the speed, and calculate its value at t = 5.0803 s.
The derivative is
V(t) = dh/dt = -9.8t + 24.5
Plug in the value of t that you got (which was correct) and compute V
The derivative is
V(t) = dh/dt = -9.8t + 24.5
Plug in the value of t that you got (which was correct) and compute V
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