Asked by Anonymous
find the cubic equation that has a y intercept of (0, -4) and has roots at x=1, x=2, and x= -5
Answers
Answered by
drwls
y = a (x-1)(x-2)(x+5) = 0
At x=0, 10 a = -4, so a = -0.4
y = (0.4)(x^3 +2x^2 -13x +10) = 0
At x=0, 10 a = -4, so a = -0.4
y = (0.4)(x^3 +2x^2 -13x +10) = 0
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