Asked by P1
.
solve the cubic equation
2x^3-11x^2+18x-8=0
show workings
#thanks
solve the cubic equation
2x^3-11x^2+18x-8=0
show workings
#thanks
Answers
Answered by
Reiny
They probably expect you to use factoring, so try factors of 8
so x = ±1, ± 2 , ± 4 would be values to start with,
Sure enough on the third try, x = 2 works
Thus x-2 is a factor and by synthetic division,
2x^3-11x^2+18x-8=0
(x-2)(2x^2 -7x + 4) = 0
so one root is x = 2,
find the other two by using the quadratic formula on the second factor.
so x = ±1, ± 2 , ± 4 would be values to start with,
Sure enough on the third try, x = 2 works
Thus x-2 is a factor and by synthetic division,
2x^3-11x^2+18x-8=0
(x-2)(2x^2 -7x + 4) = 0
so one root is x = 2,
find the other two by using the quadratic formula on the second factor.
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