If total energy is constant then
(1/2) m v^ 2 + 5 x^2 = constant = c
.3 v^2 + 5 x^2 = c
.3 (3)^2 + 5 (1.2)^2 = c
solve for c
then put in x = 0
.3 v^2 = c
A 0.60-kg particle moves along the x-axis. Its potential energy is given by U(x)=5x^2, where U is joules and x is in meters. If the particle has a speed of 3.0m/s what it is at x=1.2m, its speed when it is at the origin is?
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