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Find the equations for the lines tangent to the ellipse 4x^2+y^2=72 that are perpendicular to the line x+2y+3=0

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If a line is perpendicular to
x+2y+3=0 (or y = -x/2 - 3/2),
the slope of the line must be 2.

Solve the equation dy/dx = 2.

y = sqrt(72 - 4x^2)
dy/dx = (-4x)/sqrt(72 - 4x^2) = 2

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