Asked by Rachel
A line has parametric equations x=7t-2 and y=-4+3t. What is the slope of the line representing the direct relationship between x and y?
Answers
Answered by
Reiny
from x=7t-2
t = (x+2)/7
from y=-4+3t
t = (y+4)/3
(x+2)/7 = (y+4)/3
3x + 6 = 7y + 28
3x - 7y = 22 ---> slope = 3/7
t = (x+2)/7
from y=-4+3t
t = (y+4)/3
(x+2)/7 = (y+4)/3
3x + 6 = 7y + 28
3x - 7y = 22 ---> slope = 3/7