Asked by jethro
can someone show the steps 6*1/2-4[2-3(4*1/2-3)]=-17 in two step equation in algrebra
Answers
Answered by
Reiny
6*1/2-4[2-3(4*1/2-3)]
= 6*1/2-4[2-3(2-3)]
= 6*1/2-4[2-3(-1)]
= 6*1/2-4[2+3]
= 6*1/2-4[5]
= 3 - 20
= -17
of course you could plug
6*1/2-4(2-3(4*1/2-3))
into the Google search window to get
http://www.google.com/search?rls=ig&hl=en&source=hp&biw=1662&bih=912&q=6*1%2F2-4%282-3%284*1%2F2-3%29%29&aq=f&aqi=&aql=&oq=&gs_rfai=
Notice that you have to replace the [ ] brackets with ( )
= 6*1/2-4[2-3(2-3)]
= 6*1/2-4[2-3(-1)]
= 6*1/2-4[2+3]
= 6*1/2-4[5]
= 3 - 20
= -17
of course you could plug
6*1/2-4(2-3(4*1/2-3))
into the Google search window to get
http://www.google.com/search?rls=ig&hl=en&source=hp&biw=1662&bih=912&q=6*1%2F2-4%282-3%284*1%2F2-3%29%29&aq=f&aqi=&aql=&oq=&gs_rfai=
Notice that you have to replace the [ ] brackets with ( )
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