an iron ore contains 50.0% Fe2O3. How many grams of pure iron could be contained from 200 grams of this ore?

Answer 1

200 g x 0.50 = ?? g Fe2O3.
moles Fe2O3 = ??g/molar mass Fe2O3.
moles Fe = 3 x moles Fe2O3.
g Fe = moles Fe x molar mass Fe.

Answer 2

70 g Fe

Answer 3

Iron ore contain 50% of Fe2O3
200g of iron ore contains 0.5×200= 100g of Fe2O3.
RAM = 160
Fe2 = 112
Grams of pure iron in 100g of Fe2O3 = 112/160×100 = 70g.