Asked by guest
                You are asked to make 43 grams of iron (Fe) from iron III oxide (Fe2O3) and carbon monoxide (CO) as shown in the chemical equation below. 
Fe2O3 + 3CO → 2Fe + 3CO2
How many grams of iron III oxide must you use?
Question 10 options:
61.49 g
122.99 g
0.77 g
6863 g
            
        Fe2O3 + 3CO → 2Fe + 3CO2
How many grams of iron III oxide must you use?
Question 10 options:
61.49 g
122.99 g
0.77 g
6863 g
Answers
                    Answered by
            DrBob222
            
    Fe2O3 + 3CO → 2Fe + 3CO2 
moles Fe you want = grams/atomic mass = ?
Using the coefficients in the balanced equation, convert mols Fe you want to mols Fe2O3 you need. That is mols Fe from above x (1 mole Fe2O3/2 mols Fe) = ?
Now convert mols Fe2O3 to grams Fe2O3. g = mols x molar mass = ?
Post our work if you get stuck.
    
moles Fe you want = grams/atomic mass = ?
Using the coefficients in the balanced equation, convert mols Fe you want to mols Fe2O3 you need. That is mols Fe from above x (1 mole Fe2O3/2 mols Fe) = ?
Now convert mols Fe2O3 to grams Fe2O3. g = mols x molar mass = ?
Post our work if you get stuck.
                    Answered by
            help
            
    we need an answer bud
    
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