Question

You are asked to make 43 grams of iron (Fe) from iron III oxide (Fe2O3) and carbon monoxide (CO) as shown in the chemical equation below.

Fe2O3 + 3CO → 2Fe + 3CO2

How many grams of iron III oxide must you use?

Question 10 options:

61.49 g


122.99 g


0.77 g


6863 g

Answer 1

Fe2O3 + 3CO → 2Fe + 3CO2

moles Fe you want = grams/atomic mass = ?
Using the coefficients in the balanced equation, convert mols Fe you want to mols Fe2O3 you need. That is mols Fe from above x (1 mole Fe2O3/2 mols Fe) = ?
Now convert mols Fe2O3 to grams Fe2O3. g = mols x molar mass = ?
Post our work if you get stuck.

Answer 2

we need an answer bud