Question

Solve the system of equations x, minus, 3, y, equals, 0x−3y=0 and 3, x, minus, 6, y, equals, 93x−6y=9 by combining the equations.
Below, two sets of the two equations are shown. The first set has input boxes in front of each equation to put a number to multiply it by. When you enter a number, the corresponding equation below changes to be the result of the multiplication. Under the second set, a resulting equation is shown with input boxes for the coefficients and constant. Then, there is a "try" button. When you press the try button, if your answer is correct, it will be placed on the page and a new question will appear with a new input box. This process will continue until the final answer area appears with the submit button.
left parenthesis, x(x minus, 3, y−3y equals= 0, right parenthesis0)
left parenthesis, 3, x(3x minus, 6, y−6y equals= 9, right parenthesis9)
xx minus, 3, y−3y equals= 00
3, x3x minus, 6, y−6y equals= 99
0
0xx plus+
0
0yy equals=

Answer 1

x - 3y = 0
3x - 6y = 9

Multiply the first equation by -3: -3x + 9y = 0.
Add this to the second equation:
(3x - 6y) + (-3x + 9y) = 9 + 0 => 3y = 9 => y = 3.

Then from x - 3y = 0: x = 3y = 9.

Solution: x = 9, y = 3.