Asked by 5
Solve the system of equations.
-4x + 6у = 38
x - 5y = -20 (1 point)
(-35, - 3)
(5, 3)
(35, - 3)
(-5,3)
-4x + 6у = 38
x - 5y = -20 (1 point)
(-35, - 3)
(5, 3)
(35, - 3)
(-5,3)
Answers
Answered by
GPT-4o mini
To solve the system of equations, we start by rewriting the equations:
1. \(-4x + 6y = 38\)
2. \(x - 5y = -20\)
Now, we can solve one of the equations for one variable and substitute it into the other. Let's solve the second equation for \(x\):
From \(x - 5y = -20\):
\[
x = 5y - 20
\]
Now, substitute \(x\) into the first equation:
\[
-4(5y - 20) + 6y = 38
\]
Distributing \( -4 \):
\[
-20y + 80 + 6y = 38
\]
Combine like terms:
\[
-14y + 80 = 38
\]
Subtract 80 from both sides:
\[
-14y = 38 - 80
\]
\[
-14y = -42
\]
Now, divide by -14:
\[
y = \frac{-42}{-14} = 3
\]
Now that we have \(y\), we can find \(x\) using the equation \(x = 5y - 20\):
\[
x = 5(3) - 20
\]
\[
x = 15 - 20
\]
\[
x = -5
\]
So, the solution to the system of equations is \( (x, y) = (-5, 3) \).
Thus, the correct answer is:
\[
\boxed{(-5, 3)}
\]
1. \(-4x + 6y = 38\)
2. \(x - 5y = -20\)
Now, we can solve one of the equations for one variable and substitute it into the other. Let's solve the second equation for \(x\):
From \(x - 5y = -20\):
\[
x = 5y - 20
\]
Now, substitute \(x\) into the first equation:
\[
-4(5y - 20) + 6y = 38
\]
Distributing \( -4 \):
\[
-20y + 80 + 6y = 38
\]
Combine like terms:
\[
-14y + 80 = 38
\]
Subtract 80 from both sides:
\[
-14y = 38 - 80
\]
\[
-14y = -42
\]
Now, divide by -14:
\[
y = \frac{-42}{-14} = 3
\]
Now that we have \(y\), we can find \(x\) using the equation \(x = 5y - 20\):
\[
x = 5(3) - 20
\]
\[
x = 15 - 20
\]
\[
x = -5
\]
So, the solution to the system of equations is \( (x, y) = (-5, 3) \).
Thus, the correct answer is:
\[
\boxed{(-5, 3)}
\]
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