If the area of a square is 9x2-12xy+4y2, what is the perimeter of the square in terms of x and y.

*its 9x squared and 4y squared

i have several problems like this on my homework if you show me how to do this one im sure i could figure out the rest

1 answer

Since the 4 sides are equal:
A = S^2 = 9X^2 - 12XY + 4Y^2,
The trinomial is a perfect square:

S^2 = (3x - 2y)^2,
Take the sqrt of both sides:
S = 3X - 2Y = Length of each side,

p = 4*s = 4(3x -2y), or 12x - 8y.