A mixture contains only NaCl and Fe(NO3)3. A .456 gram sample of the mixture is dissolved in water and an excess of NaOH is added, producing a precipitate of Fe(OH)3. The precipitate is dried and filtered, and its mass is determined to be .107 g.

Question

The mass of iron in the sample?
The mass of Fe(NO3)3 in the sample?
the mass percent of Fe(NO3)3 in the sample?

Answer 1

mass Fe = 0.107 x (1 mol Fe(OH)3/molar mass Fe(OH)3) x (1 mol Fe/1 mol Fe(OH)3) x (molar mass Fe/1 mol Fe) = ??

mass Fe(NO3)3 = mass Fe(OH)3 x (molar mass Fe(NO3)3/molar mass Fe(OH)3 = xx

%Fe(NO3)3 = (mass Fe(NO3)3/mass sample)*100 = xx

Answer 2

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