To calculate the mass percent of NaCl in the mixture, we need to determine the amount of NaCl and sucrose present in the solution.
First, we need to find the moles of NaCl and sucrose using the ideal gas law:
PV = nRT
Where:
P = osmotic pressure (8.29 atm)
V = volume of the solution (250 mL)
n = moles of solute
R = ideal gas constant (0.0821 L路atm/mol路K)
T = temperature in Kelvin (23 + 273 = 296 K)
Rearranging the ideal gas equation to solve for moles:
n = PV / RT
For NaCl:
n(NaCl) = (8.29 atm) 脳 (0.250 L) / (0.0821 L路atm/mol路K) 脳 (296 K)
Next, we calculate the moles of sucrose using the same formula:
n(C12H22O11) = (8.29 atm) 脳 (0.250 L) / (0.0821 L路atm/mol路K) 脳 (296 K)
To convert the moles of NaCl and sucrose to grams, we use their respective molar masses:
Molar mass of NaCl = 58.44 g/mol
Molar mass of C12H22O11 = (12.01 脳 12) + (1.01 脳 22) + (16.00 脳 11) = 342.3 g/mol
Now, we can calculate the mass percent of NaCl:
mass percent of NaCl = (mass of NaCl / total mass of solution) 脳 100
The mass of NaCl can be found using the moles of NaCl and its molar mass:
mass of NaCl = moles of NaCl 脳 molar mass of NaCl
Finally, the total mass of the solution is the sum of the masses of NaCl and sucrose:
total mass of solution = mass of NaCl + mass of sucrose
By substituting the values into the formula, we can find the mass percent of NaCl in the mixture.