Ask a New Question

Asked by Kaylee

How many milliliters of 8.40×10^2M Ba(OH)2(aq) are required to titrate 48.65mL of 5.26×10^2M HNO3?
15 years ago

Answers

Answered by bobpursley
volume acid*normality acid=volumebase*Normally base

48.65ml*5.26E2M=2*V*8.40E2M

solve for Volume, V
15 years ago
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions

How many milliliters of .100 M HNO3 are needed to neutralize 58.5 mL of .0100 Al(0H)3? How many milliliters of 0.729 M NaOH are needed to prepare 150.0 mL of 0.122 M NaOH? 25.1 mL How many milliliters of 5.50 M HCl must be diluted to make 350. mL of a 0.500 M solution? How many milliliters of 0.736 M H3PO4 are required to react with 238 mL of 0.160 M Ba(OH)2 if the pr... What is 3/10 in milliliters How many milliliters of a .5M HNO3 (aq) is needed to completely neutralize 100mL of a 0.10M KOH (aq)... How many milliliters of 0.237 M HCl are needed to react with 52.2g of CaCO3? 2HCl(aq) + CaCO3(s)... how many milliliters of 0.125 M H2SO4 are needed to neutralize 0.200 g of NaOH? How many milliliters of 0.748 M Mg(NO3)2 contain 1.700 g of Mg(NO3)2
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use