Question
One way you could approach this problem is to rewrite both numbers in terms of the same power of 10. Start by rewriting 600,000 as a number times
103.
Chocolate consumed by Town B
Chocolate consumed by Town A
=
600,000
1.5·103
=
· 103
1.5·103
103.
Chocolate consumed by Town B
Chocolate consumed by Town A
=
600,000
1.5·103
=
· 103
1.5·103
Answers
GPT-4o mini
To compare the chocolate consumed by Town B and Town A, you can start by rewriting both numbers in terms of the same power of 10. Given the chocolate consumed by Town A is \( 1.5 \times 10^3 \) (or 1500) and Town B consumed 600,000, we can express 600,000 in terms of \( 10^3 \).
1. **Rewrite 600,000**:
\[
600,000 = 6 \times 10^5
\]
2. **Convert \( 6 \times 10^5 \) to \( 10^3 \)**:
Since \( 10^5 \) can also be expressed as \( 10^3 \times 10^2 \), we can rewrite \( 600,000 \) as follows:
\[
600,000 = 6 \times 10^5 = 6 \times (10^3 \times 10^2) = 6 \times 10^3 \times 100
\]
3. **Now express it in units of \( 10^3 \)**:
Here,
\[
600,000 = 600 \times 10^3
\]
Now we have both towns' chocolate consumption in units of \( 10^3 \):
- Chocolate consumed by Town A: \( 1.5 \times 10^3 \)
- Chocolate consumed by Town B: \( 600 \times 10^3 \)
4. **Set up the ratio**:
Now we can compare them by forming a ratio:
\[
\text{Chocolate consumed by Town B} \div \text{Chocolate consumed by Town A} = \frac{600 \times 10^3}{1.5 \times 10^3}
\]
Since \( 10^3 \) cancels out, we simplify this to:
\[
\frac{600}{1.5}
\]
5. **Calculate the ratio**:
Performing the division:
\[
\frac{600}{1.5} = 400
\]
Thus, Town B consumed **400 times** more chocolate than Town A.
1. **Rewrite 600,000**:
\[
600,000 = 6 \times 10^5
\]
2. **Convert \( 6 \times 10^5 \) to \( 10^3 \)**:
Since \( 10^5 \) can also be expressed as \( 10^3 \times 10^2 \), we can rewrite \( 600,000 \) as follows:
\[
600,000 = 6 \times 10^5 = 6 \times (10^3 \times 10^2) = 6 \times 10^3 \times 100
\]
3. **Now express it in units of \( 10^3 \)**:
Here,
\[
600,000 = 600 \times 10^3
\]
Now we have both towns' chocolate consumption in units of \( 10^3 \):
- Chocolate consumed by Town A: \( 1.5 \times 10^3 \)
- Chocolate consumed by Town B: \( 600 \times 10^3 \)
4. **Set up the ratio**:
Now we can compare them by forming a ratio:
\[
\text{Chocolate consumed by Town B} \div \text{Chocolate consumed by Town A} = \frac{600 \times 10^3}{1.5 \times 10^3}
\]
Since \( 10^3 \) cancels out, we simplify this to:
\[
\frac{600}{1.5}
\]
5. **Calculate the ratio**:
Performing the division:
\[
\frac{600}{1.5} = 400
\]
Thus, Town B consumed **400 times** more chocolate than Town A.