Question
The area of the circular base of a cylinder is 36π square units. The height of the cylinder is 2 units.
What is the lateral area of the cylinder? Express the answer in terms of π.
12π square units
24π square units
60π square units
72π square units
What is the lateral area of the cylinder? Express the answer in terms of π.
12π square units
24π square units
60π square units
72π square units
Answers
Answered by
GPT-4o mini
To find the lateral area of the cylinder, we need to use the formula for the lateral surface area of a cylinder, which is given by:
\[
\text{Lateral Area} = 2 \pi r h
\]
where \( r \) is the radius of the base of the cylinder and \( h \) is the height.
We know the area of the circular base of the cylinder is \( 36\pi \) square units. The area \( A \) of a circle is given by:
\[
A = \pi r^2
\]
Setting this equal to the area of the base:
\[
\pi r^2 = 36\pi
\]
We can simplify this by dividing both sides by \( \pi \):
\[
r^2 = 36
\]
Taking the square root of both sides gives us:
\[
r = 6
\]
Now, we know that the height \( h \) of the cylinder is 2 units. We can substitute \( r \) and \( h \) into the lateral area formula:
\[
\text{Lateral Area} = 2 \pi (6) (2)
\]
Calculating this gives:
\[
\text{Lateral Area} = 2 \pi \cdot 6 \cdot 2 = 24\pi
\]
Thus, the lateral area of the cylinder is:
\[
\boxed{24\pi} \text{ square units}
\]
\[
\text{Lateral Area} = 2 \pi r h
\]
where \( r \) is the radius of the base of the cylinder and \( h \) is the height.
We know the area of the circular base of the cylinder is \( 36\pi \) square units. The area \( A \) of a circle is given by:
\[
A = \pi r^2
\]
Setting this equal to the area of the base:
\[
\pi r^2 = 36\pi
\]
We can simplify this by dividing both sides by \( \pi \):
\[
r^2 = 36
\]
Taking the square root of both sides gives us:
\[
r = 6
\]
Now, we know that the height \( h \) of the cylinder is 2 units. We can substitute \( r \) and \( h \) into the lateral area formula:
\[
\text{Lateral Area} = 2 \pi (6) (2)
\]
Calculating this gives:
\[
\text{Lateral Area} = 2 \pi \cdot 6 \cdot 2 = 24\pi
\]
Thus, the lateral area of the cylinder is:
\[
\boxed{24\pi} \text{ square units}
\]
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