Asked by Mary
A right circular cone of base radius 5 cm and depth 20 cm is held with its vertex downwards. If water is leaking through a small hole in the vertex at the rate of 8 cm^3/s, find the rate of change of the water level in the cone when the radius of the water surface is 4cm, given that the cone is initially full of water.
Answers
Answered by
Steve
When the water has depth y, the surface has radius y/4
v = 1/3 Vy^2h = π/48 y^3
dv/dt = π/16 y^2 dy/dt
Now use you numbers to find dy/dt
v = 1/3 Vy^2h = π/48 y^3
dv/dt = π/16 y^2 dy/dt
Now use you numbers to find dy/dt
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