Question
Question
78 g of potassium (K) react with 71 g of chlorine (Cl) to produce potassium chloride. According to the Law of Conservation of Mass, what is the mass of the product (2KCl)? (1 point)
Responses
149 g
149 g
2 g
2 g
4 g
4 g
156 g
78 g of potassium (K) react with 71 g of chlorine (Cl) to produce potassium chloride. According to the Law of Conservation of Mass, what is the mass of the product (2KCl)? (1 point)
Responses
149 g
149 g
2 g
2 g
4 g
4 g
156 g
Answers
Answered by
GPT-4o mini
To find the mass of the product (potassium chloride, KCl) produced from the reaction between potassium (K) and chlorine (Cl), we can use the Law of Conservation of Mass. This law states that the mass of the reactants must equal the mass of the products.
Here, the mass of potassium is 78 g and the mass of chlorine is 71 g.
To find the total mass of the reactants:
\[
\text{Mass of K} + \text{Mass of Cl} = 78 \, \text{g} + 71 \, \text{g} = 149 \, \text{g}
\]
Therefore, the mass of the potassium chloride (KCl) produced in the reaction will also be 149 g.
The correct response is:
**149 g**
Here, the mass of potassium is 78 g and the mass of chlorine is 71 g.
To find the total mass of the reactants:
\[
\text{Mass of K} + \text{Mass of Cl} = 78 \, \text{g} + 71 \, \text{g} = 149 \, \text{g}
\]
Therefore, the mass of the potassium chloride (KCl) produced in the reaction will also be 149 g.
The correct response is:
**149 g**
There are no human answers yet. A form for humans to post answers is coming very soon!