Question

Graph the linear equation by the​ point-plotting method or by finding intercepts.
−5y−15=0

Answer 1

To graph the linear equation \(-5y - 15 = 0\), we can first rearrange it into a more standard form.

1. **Isolate \(y\)**:
\[
-5y = 15
\]
\[
y = -3
\]

This tells us that the equation represents a horizontal line where \(y\) is constantly equal to \(-3\).

### Finding Points

To graph this line, we can identify a few points:

- When \(x = 0\), \(y = -3\) (point: \((0, -3)\))
- When \(x = 1\), \(y = -3\) (point: \((1, -3)\))
- When \(x = -1\), \(y = -3\) (point: \((-1, -3)\))

### Graphing

1. **Sketch the Coordinates**:
- Plot the points \((0, -3)\), \((1, -3)\), and \((-1, -3)\) on a coordinate plane.

2. **Draw the Line**:
- Since \(y\) does not change with \(x\), you will draw a horizontal line through these points at \(y = -3\).

### Conclusion

The graph of the equation \(-5y - 15 = 0\) is a horizontal line located at \(y = -3\). The line will extend infinitely in both directions along the \(x\)-axis at that \(y\) value.