Question

Graph the linear equation y = 2/3x - 1
A. (0,1) (-2,-2)
B. (0,-2) (1,-9)
C. (1,2) (0,-4)
D. (3,1) (0,-1)

Answer 1

To graph the linear equation \( y = \frac{2}{3}x - 1 \), we can find two points that satisfy the equation.

1. Find the y-intercept by setting \( x = 0 \):
\[
y = \frac{2}{3}(0) - 1 = -1
\]
So, the y-intercept is \( (0, -1) \).

2. Find another point by selecting a value for \( x \). Let's choose \( x = 3 \):
\[
y = \frac{2}{3}(3) - 1 = 2 - 1 = 1
\]
So, another point is \( (3, 1) \).

Now we have two points: \( (0, -1) \) and \( (3, 1) \).

Now, let's check the provided options:

A. \( (0, 1) (-2, -2) \)
B. \( (0, -2) (1, -9) \)
C. \( (1, 2) (0, -4) \)
D. \( (3, 1) (0, -1) \)

The points \( (0, -1) \) and \( (3, 1) \) correspond to option D, which is correct.

Thus, the answer is:
**D. (3, 1) (0, -1)**