Question

2 wholes and 1 half plus 3 fourths

Answer 1

To solve \(2\) wholes and \(1\) half plus \(3\) fourths, we can first convert everything into fractions:

- \(2\) wholes = \(2\) or \(\frac{2}{1}\)
- \(1\) half = \(\frac{1}{2}\)
- \(3\) fourths = \(\frac{3}{4}\)

Now, let's express \(2\) as a fraction with a common denominator that works for \(\frac{1}{2}\) and \(\frac{3}{4}\). The least common denominator (LCD) of \(2\) and \(4\) is \(4\).

Now convert \(2\) into a fraction with the denominator \(4\):

\[
2 = \frac{8}{4}
\]

Now we can express \(2\) and \(1\) half in terms of fourths:

\[
2 + 1/2 = \frac{8}{4} + \frac{1}{2} = \frac{8}{4} + \frac{2}{4} = \frac{10}{4}
\]

Now, add \(3\) fourths:

\[
\frac{10}{4} + \frac{3}{4} = \frac{13}{4}
\]

Finally, we can simplify \(\frac{13}{4}\).

\(\frac{13}{4}\) can be expressed as a mixed number:

\[
3 \frac{1}{4}
\]

Thus, \(2\) wholes and \(1\) half plus \(3\) fourths equals \(3\) and \(1/4\) or \(\frac{13}{4}\).