To solve \(2\) wholes and \(1\) half plus \(3\) fourths, we can first convert everything into fractions:
- \(2\) wholes = \(2\) or \(\frac{2}{1}\)
- \(1\) half = \(\frac{1}{2}\)
- \(3\) fourths = \(\frac{3}{4}\)
Now, let's express \(2\) as a fraction with a common denominator that works for \(\frac{1}{2}\) and \(\frac{3}{4}\). The least common denominator (LCD) of \(2\) and \(4\) is \(4\).
Now convert \(2\) into a fraction with the denominator \(4\):
\[ 2 = \frac{8}{4} \]
Now we can express \(2\) and \(1\) half in terms of fourths:
\[ 2 + 1/2 = \frac{8}{4} + \frac{1}{2} = \frac{8}{4} + \frac{2}{4} = \frac{10}{4} \]
Now, add \(3\) fourths:
\[ \frac{10}{4} + \frac{3}{4} = \frac{13}{4} \]
Finally, we can simplify \(\frac{13}{4}\).
\(\frac{13}{4}\) can be expressed as a mixed number:
\[ 3 \frac{1}{4} \]
Thus, \(2\) wholes and \(1\) half plus \(3\) fourths equals \(3\) and \(1/4\) or \(\frac{13}{4}\).