Question
x + 2 wholes 1/2 < 2 wholes 1/2 solve the inequality
Answers
GPT-4o mini
To solve the inequality \( x + 2 \frac{1}{2} < 2 \frac{1}{2} \), first convert the mixed numbers into improper fractions or decimals for easier manipulation.
1. Convert \( 2 \frac{1}{2} \) to an improper fraction:
\[
2 \frac{1}{2} = 2 \times 2 + 1 = 5 \quad \text{(or as an improper fraction: } \frac{5}{2})
\]
2. Now rewrite the inequality:
\[
x + 2 \frac{1}{2} < 5
\]
Converting \( 2 \frac{1}{2} \) gives:
\[
2 \frac{1}{2} = 2 + \frac{1}{2} = \frac{5}{2}
\]
So the inequality is:
\[
x + \frac{5}{2} < 5
\]
3. Now eliminate the fraction by subtracting \( \frac{5}{2} \) from both sides:
\[
x < 5 - \frac{5}{2}
\]
Converting \( 5 \) to a fraction with a denominator of \( 2 \):
\[
5 = \frac{10}{2}
\]
Now perform the subtraction:
\[
x < \frac{10}{2} - \frac{5}{2} = \frac{5}{2}
\]
4. Therefore, the solution to the inequality is:
\[
x < \frac{5}{2} \quad \text{or} \quad x < 2 \frac{1}{2}
\]
So, in conclusion, the solution is:
\[
x < 2 \frac{1}{2}
\]
1. Convert \( 2 \frac{1}{2} \) to an improper fraction:
\[
2 \frac{1}{2} = 2 \times 2 + 1 = 5 \quad \text{(or as an improper fraction: } \frac{5}{2})
\]
2. Now rewrite the inequality:
\[
x + 2 \frac{1}{2} < 5
\]
Converting \( 2 \frac{1}{2} \) gives:
\[
2 \frac{1}{2} = 2 + \frac{1}{2} = \frac{5}{2}
\]
So the inequality is:
\[
x + \frac{5}{2} < 5
\]
3. Now eliminate the fraction by subtracting \( \frac{5}{2} \) from both sides:
\[
x < 5 - \frac{5}{2}
\]
Converting \( 5 \) to a fraction with a denominator of \( 2 \):
\[
5 = \frac{10}{2}
\]
Now perform the subtraction:
\[
x < \frac{10}{2} - \frac{5}{2} = \frac{5}{2}
\]
4. Therefore, the solution to the inequality is:
\[
x < \frac{5}{2} \quad \text{or} \quad x < 2 \frac{1}{2}
\]
So, in conclusion, the solution is:
\[
x < 2 \frac{1}{2}
\]