No.
Your equations are troubling, as it reveals you have no idea what you are doing.
Work input= KE output
Netforce*distance= 1/2 m v^2
4500*100= 1/2 *1400*v^2
Solve for v. This is about ten times what you thought.
A car with mass of 1400kg is towed with a net force of 4500N. the car starts from rest, find the speed of the car traveled after it traveled 100m.
W=FnetX distance=ma x distance
4500N=(1/2)1400kg V^2
2.5m/s=V
is this right? if not what am i doing wrong?
1 answer
1 answer