Asked by David
Calculate the total constant force needed to accelerate a vehicle with mass 1400kg and tractive resistance of 320N from 19km/h to 95km/h over a distance of 0.8km on a horizontal plane.show working?
Answers
Answered by
herp_derp
ah...DANNY..we meet again...
not sure if this is right but i'll take a shot at it...
1. convert all the info into MKS units (MKS = meters, kilograms, seconds)
19 km/hr = 5.277 m/s
95 km/hr = 26.388 m/s
0.8 km = 800 m
2. start with this equation:
vf^2 = vi^2 + 2ad
then, solve for "a"
a = (vf^2 - vi^2)/(2d)
plug in the numbers...
((26.388 m/s)^2 - (5.277 m/s)^2)/(2 x 800 m) = 0.4178 m/s^2
3. then we take care of those vectors...
Fo - Fe = Fc
ma - Fe = Fc
(1400 kg)(0.4178 m/s^2) - (320 N) = 264.92 N
-----
remember DANNY.....HERP THE DERP!!!
not sure if this is right but i'll take a shot at it...
1. convert all the info into MKS units (MKS = meters, kilograms, seconds)
19 km/hr = 5.277 m/s
95 km/hr = 26.388 m/s
0.8 km = 800 m
2. start with this equation:
vf^2 = vi^2 + 2ad
then, solve for "a"
a = (vf^2 - vi^2)/(2d)
plug in the numbers...
((26.388 m/s)^2 - (5.277 m/s)^2)/(2 x 800 m) = 0.4178 m/s^2
3. then we take care of those vectors...
Fo - Fe = Fc
ma - Fe = Fc
(1400 kg)(0.4178 m/s^2) - (320 N) = 264.92 N
-----
remember DANNY.....HERP THE DERP!!!
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.