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If I take a glob of mud and throw it against a wall with the speed of V and stops in time T and than I take a ball and throw it...Asked by Allen
If I take a glob of mud and throw it against a wall with the speed of V and stops in time T and than I take a ball and throw it and it hits the wall with speed V and leaves the wall a time T later at a speed of 0.5V and they both have same value and mass, which one involves a greater total force on the object.
I think it is the ball but to be honest I don't understand why-I'm thinking because it is pushed off the wall once it hits it? Newton's laws?
Could you give me some direction, please?
I think it is the ball but to be honest I don't understand why-I'm thinking because it is pushed off the wall once it hits it? Newton's laws?
Could you give me some direction, please?
Answers
Answered by
bobpursley
force*time=changemomentum
if mv was the mud ball momentum
then mv+1/2 mv was the CHANGE of momentum for the ball.
Remember Vf for the ball= -V/2, its intial velocity was V
changemomentum=m (Vf-Vi)=m(3/2 V)
if mv was the mud ball momentum
then mv+1/2 mv was the CHANGE of momentum for the ball.
Remember Vf for the ball= -V/2, its intial velocity was V
changemomentum=m (Vf-Vi)=m(3/2 V)
Answered by
Allen
Thank you
Answered by
abdallah
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