If I take a glob of mud and throw it against a wall with the speed of V and stops in time T and than I take a ball and throw it and it hits the wall with speed V and leaves the wall a time T later at a speed of 0.5V and they both have same value and mass, which one involves a greater total force on the object.
I think it is the ball but to be honest I don't understand why-
Could you give me some direction, please?
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physics question here.
need physics help
need physics help here.
Force is the rate of change of momentum, equal to mass*velocity.
Both objects hit the wall and the change of velocity (and hence momentum) takes place in time T.
In the case of the mud-pie, the rate of change of momentum is m(0-V)/T = -mV/T, since the final velocity is 0 (inelastic impact).
In the case of the bass, the rebound velocity is 0.5V, hence the change of momentum is m(-0.5V-V)/T=-1.5mV/T.
Thus we conclude that the absolute value of the force on the wall is greater in the case of the__________.
Both objects hit the wall and the change of velocity (and hence momentum) takes place in time T.
In the case of the mud-pie, the rate of change of momentum is m(0-V)/T = -mV/T, since the final velocity is 0 (inelastic impact).
In the case of the bass, the rebound velocity is 0.5V, hence the change of momentum is m(-0.5V-V)/T=-1.5mV/T.
Thus we conclude that the absolute value of the force on the wall is greater in the case of the__________.
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