Is this the correct graph of the equation y=1/5x
?

(1 point)
Responses

Yes, it is the correct graph because the slope =5/1
.


No, it is not the correct graph because the slope m=rise/run=1/5
.

Yes, it is the correct graph because the ordered pair (0, 0)
satisfies the equation and the slope m=rise/run=1/5
..

No, it is not the correct graph because the ordered pair (1, 5)
is not a point on the graph of y=1/5x

Answers

Answered by GPT-4o mini
To assess whether the provided statements about the graph of the equation \( y = \frac{1}{5}x \) are correct, let's analyze the equation and the choices given.

1. **Understanding the equation:** The equation \( y = \frac{1}{5}x \) indicates that the slope \( m \) is \( \frac{1}{5} \). This means for every 5 units you move horizontally (run), you move up 1 unit (rise).

2. **Evaluating the responses:**

- **Response 1:** "Yes, it is the correct graph because the slope = 5/1."
- This is incorrect because the slope is \( \frac{1}{5} \), not \( \frac{5}{1} \).

- **Response 2:** "No, it is not the correct graph because the slope m=rise/run=1/5."
- This is a valid response if the graph displayed a different slope. If the graph was indeed wrong, then this statement would be correct.

- **Response 3:** "Yes, it is the correct graph because the ordered pair (0, 0) satisfies the equation and the slope m=rise/run=1/5."
- The point (0, 0) does satisfy the equation, and the slope is indeed \( \frac{1}{5} \). If the graph also shows the correct slope, this response would be valid.

- **Response 4:** "No, it is not the correct graph because the ordered pair (1, 5) is not a point on the graph of y=1/5x."
- This statement is correct, since if you substitute \( x = 1 \) into the equation, \( y \) should equal \( \frac{1}{5}(1) = \frac{1}{5} \), not 5. Therefore, (1, 5) wouldn't be on the graph.

Based on this analysis, if the graph shows a slope different from \( \frac{1}{5} \) or does not include the correct points calculated, **responses 2 and 4** could be valid depending on the context of the actual graph in question.

So, the best response would be **Response 4** if indeed (1,5) is on the graph, which contradicts the equation.
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