Question

Is this the correct graph of the equation y=15x
point 1 (0, 0) point 2 (5, 1)
?

(1 point)
Responses

No, it is not the correct graph because the ordered pair (1, 5)
is not a point on the graph of y=15x
No, it is not the correct graph because the ordered pair left parenthesis 1 comma 5 right parenthesis is not a point on the graph of y equals Start Fraction 1 over 5 End Fraction x

Yes, it is the correct graph because the slope =51
.
Yes, it is the correct graph because the slope equals Start Fraction 5 over 1 End Fraction .

Yes, it is the correct graph because the ordered pair (0, 0)
satisfies the equation and the slope m=riserun=15
.
Yes, it is the correct graph because the ordered pair left parenthesis 0 comma 0 right parenthesis satisfies the equation and the slope m equals Start Fraction rise over run End Fraction equals Start Fraction 1 over 5 End Fraction .

No, it is not the correct graph because the slope m=riserun=15
.

Answer 1

To determine whether the points provided (0, 0) and (5, 1) are on the graph of the equation \( y = 15x \), we can evaluate each point:

1. For the point (0, 0):
- Substitute \( x = 0 \) into the equation:
\[
y = 15(0) = 0
\]
- The point (0, 0) satisfies the equation.

2. For the point (5, 1):
- Substitute \( x = 5 \) into the equation:
\[
y = 15(5) = 75
\]
- The point (5, 1) does **not** satisfy the equation since \( y = 1 \) instead of \( y = 75 \).

Now, the equation \( y = 15x \) has a slope \( m = 15 \) (which is \(\frac{\text{rise}}{\text{run}} = 15\)).

Given the analysis, the correct answer is:
**No, it is not the correct graph because the ordered pair (5, 1) is not a point on the graph of \( y = 15x \).**