d1=1/2 .5 t^2
d2=3.1t
but d1+d2=37, and at collision, the times are the same.
1/2 .5 t^2 + 3.1t=37
this is a quadratic, so it can be solve with the quadratic equation.
Two rugby players are running towards each other. They are 37 m apart. If one is accelerating from rest at 0.5 m/s^2 and the other was already moving at 3.1 m/s and maintains her speed, a)how long before they crunch together? b)How fast was the accelerating player going?
c)How far has each player run?
2 answers
7.45