Asked by Mike
How do you solve for x^2 + square root of 6 times x -3 is > or = to 0?
Answers
Answered by
Reiny
x^2 + 6x - 3 ≥ 0
find the x-intercepts by solving
x^2+6x-3 = 0
then x ≥larger root OR x≤ smaller root
find the x-intercepts by solving
x^2+6x-3 = 0
then x ≥larger root OR x≤ smaller root
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