Asked by Sean
I still need help with this please.two knights on horseback start from rest 62 m apart and ride directly toward each other to do battle. Sir George's acceleration has a magnitude of 0.17 m/s2, while Sir Alfred's has a magnitude of 0.30 m/s2. Relative to Sir George's starting point, where do the knights collide?
Answers
Answered by
bobpursley
I will gladly critique your work.
Answered by
Sean
i don't understand the d1/d2=a1/a2.
Answered by
bobpursley
d1=distance Sr Georg goes
d2= distance Sr alfred goes
a1= sr getorge's acceleration
d1/d2=a1/a2
but d2=62-d1
so
d1*a2=(62-d1)a1
solve for d1, then solve for d2
d2= distance Sr alfred goes
a1= sr getorge's acceleration
d1/d2=a1/a2
but d2=62-d1
so
d1*a2=(62-d1)a1
solve for d1, then solve for d2
Answered by
Sean
so you set it up like the following?
d1*.30=(62-d1).17 It has been several years since I had algebra and it should be common sense but how do I get the d1 by itself?
d1*.30=(62-d1).17 It has been several years since I had algebra and it should be common sense but how do I get the d1 by itself?
Answered by
bobpursley
You are going to have a very difficult time in Physics, the question you are asking is algebra I.
.30d1+.17d1=62*.17
d1=62*.17 *1/(.47)
= 21m
.30d1+.17d1=62*.17
d1=62*.17 *1/(.47)
= 21m
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