To calculate the total bond energy in the products of the reaction \( H_2 + I_2 \rightarrow 2HI \), we need to consider the bonds formed in the products.
From the reaction, we see that 2 moles of hydroiodic acid (HI) are produced. The bond energy for the H-I bond is 297 kJ/mol.
Since there are 2 moles of HI, we need to calculate the total bond energy for 2 H-I bonds:
\[ \text{Total bond energy} = 2 \times \text{Bond energy of H-I} \] \[ \text{Total bond energy} = 2 \times 297 , \text{kJ/mol} = 594 , \text{kJ/mol} \]
Therefore, the total bond energy in the products of the reaction is 594 kJ/mol.