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Use the information in the table to answer the question. Bond Between Atoms and Their Respective Electronegativity Bond Bond En...Question
Use the information in the table to answer the question.
Bond Between Atoms and Their Respective Electronegativity
Bond Bond Energy (kJ/mol)
H-I 297
H-H 435
I-I 151
Hydrogen and iodine gases react to produce hydroiodic acid according to the reaction.
H2+I2→2HI
How much total bond energy in kJ/mol is in the products of the reaction?
(1 point)
Responses
594
594
453
453
297
297
448
448
Bond Between Atoms and Their Respective Electronegativity
Bond Bond Energy (kJ/mol)
H-I 297
H-H 435
I-I 151
Hydrogen and iodine gases react to produce hydroiodic acid according to the reaction.
H2+I2→2HI
How much total bond energy in kJ/mol is in the products of the reaction?
(1 point)
Responses
594
594
453
453
297
297
448
448
Answers
GPT-4o mini
To calculate the total bond energy in the products of the reaction \( H_2 + I_2 \rightarrow 2HI \), we need to consider the bonds formed in the products.
From the reaction, we see that 2 moles of hydroiodic acid (HI) are produced. The bond energy for the H-I bond is 297 kJ/mol.
Since there are 2 moles of HI, we need to calculate the total bond energy for 2 H-I bonds:
\[
\text{Total bond energy} = 2 \times \text{Bond energy of H-I}
\]
\[
\text{Total bond energy} = 2 \times 297 \, \text{kJ/mol} = 594 \, \text{kJ/mol}
\]
Therefore, the total bond energy in the products of the reaction is **594 kJ/mol**.
From the reaction, we see that 2 moles of hydroiodic acid (HI) are produced. The bond energy for the H-I bond is 297 kJ/mol.
Since there are 2 moles of HI, we need to calculate the total bond energy for 2 H-I bonds:
\[
\text{Total bond energy} = 2 \times \text{Bond energy of H-I}
\]
\[
\text{Total bond energy} = 2 \times 297 \, \text{kJ/mol} = 594 \, \text{kJ/mol}
\]
Therefore, the total bond energy in the products of the reaction is **594 kJ/mol**.