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Use the information in the table to answer the question. Bond Between Atoms and Their Respective Electronegativity Bond Bond En...Question
Use the information in the table to answer the question.
Bond Between Atoms and Their Respective Electronegativity
Bond Bond Energy (kJ/mol
)
H-I
297
H-H
435
I-I
151
Hydrogen and iodine gases react to produce hydroiodic acid according to the reaction.
H2+I2→2HI
How much total bond energy in kJ/mol
is in the products of the reaction?
(1 point)
Responses
453
453
448
448
297
297
594
Bond Between Atoms and Their Respective Electronegativity
Bond Bond Energy (kJ/mol
)
H-I
297
H-H
435
I-I
151
Hydrogen and iodine gases react to produce hydroiodic acid according to the reaction.
H2+I2→2HI
How much total bond energy in kJ/mol
is in the products of the reaction?
(1 point)
Responses
453
453
448
448
297
297
594
Answers
GPT-4o mini
To calculate the total bond energy in the products of the reaction \( H_2 + I_2 \rightarrow 2 HI \), we need to consider the bonds formed when the products (2 moles of HI) are produced.
Each hydroiodic acid (HI) molecule has one H-I bond. The bond energy for one H-I bond is given as 297 kJ/mol.
Since we are producing 2 moles of HI, we will have:
\[
\text{Total bond energy in products} = 2 \times \text{Bond energy of H-I}
\]
\[
\text{Total bond energy in products} = 2 \times 297 \text{ kJ/mol} = 594 \text{ kJ/mol}
\]
Thus, the total bond energy in the products of the reaction is **594 kJ/mol**.
Each hydroiodic acid (HI) molecule has one H-I bond. The bond energy for one H-I bond is given as 297 kJ/mol.
Since we are producing 2 moles of HI, we will have:
\[
\text{Total bond energy in products} = 2 \times \text{Bond energy of H-I}
\]
\[
\text{Total bond energy in products} = 2 \times 297 \text{ kJ/mol} = 594 \text{ kJ/mol}
\]
Thus, the total bond energy in the products of the reaction is **594 kJ/mol**.