Question

What are the x-intercepts of the function? y = x² + 6x + 8 x = -8 and x = -1 x = -4 and x = -2 x = 1 and x = 8 x = 4 and x = 2

Answer 1

To find the x-intercepts of the function \( y = x^2 + 6x + 8 \), we need to set \( y \) equal to zero and solve for \( x \):

\[
0 = x^2 + 6x + 8
\]

Now, we can factor the quadratic equation:

\[
0 = (x + 2)(x + 4)
\]

Setting each factor to zero gives us:

1. \( x + 2 = 0 \) → \( x = -2 \)
2. \( x + 4 = 0 \) → \( x = -4 \)

Thus, the x-intercepts of the function are:

\[
x = -2 \quad \text{and} \quad x = -4
\]

The correct answer is: **x = -4 and x = -2**.