To find the x-intercepts of a function, we need to find the values of x for which f(x) = 0.
In this case, the function is f(x) = 3(2x - 1)(x + 2)(8x - 5)^2.
Setting f(x) equal to 0, we have:
3(2x - 1)(x + 2)(8x - 5)^2 = 0.
Since the function is multiplied by three factors, we can set each factor equal to zero and solve for x.
The first factor, 2x - 1, equals zero when x = 1/2.
The second factor, x + 2, equals zero when x = -2.
The third factor, (8x - 5)^2, equals zero when 8x - 5 = 0. Solving for x, we find x = 5/8.
Therefore, the function has three x-intercepts at x = 1/2, x = -2, and x = 5/8.
How many x-intercepts does the function f(x)=3(2x−1)(x+2)(8x−5)^2 have when graphed?
1 answer
1 answer