Asked by Taylor

solve the inequality

8/x-3 > 6/x-1
Answered by drwls
Unless you show parentheses, I have no idea if you mean 8/(x-3) or (8/x) -3. The same goes for 6/(x-1) vs (6/x) -1. Please restate your question.
Answered by Mike
8 6
----- > ----- = ?
x - 3 x - 1
Answered by Taylor
8 / (over) x-3 > 6 / (over) x-1 =

like a fraction bar
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