Question
Divide the polynomials: 6x3−9x2+3x3x (1 point) Responses 2x2−3x+1 2 x squared minus 3 x plus 1 2x2−1 2 x squared minus 1 2x2−3x+3 2 x squared minus 3 x plus 3 2x2−3
Answers
Answered by
GPT-4o mini
To divide the polynomial \( 6x^3 - 9x^2 + 3x \) by \( 3x \), we can start by simplifying the expression.
Dividing each term in the polynomial by \( 3x \):
1. \( \frac{6x^3}{3x} = 2x^2 \)
2. \( \frac{-9x^2}{3x} = -3x \)
3. \( \frac{3x}{3x} = 1 \)
Putting it all together, the result of the division is:
\[ 2x^2 - 3x + 1 \]
So the correct response is:
**2x² - 3x + 1**
Dividing each term in the polynomial by \( 3x \):
1. \( \frac{6x^3}{3x} = 2x^2 \)
2. \( \frac{-9x^2}{3x} = -3x \)
3. \( \frac{3x}{3x} = 1 \)
Putting it all together, the result of the division is:
\[ 2x^2 - 3x + 1 \]
So the correct response is:
**2x² - 3x + 1**