Question

Divide the polynomials using the long division method.

what is the answer in the form P(x) = Q(x) - D(x) + R(x)

P(x) the dividend, Q(x) the quotient, R(x) the remainder ( i dont know what D(x) stands for

x+2 ) 3x^5 +5x^4 -4x^3 +2x^2 +7x +3

Answer 1

I think i got it

P(x) = 3x^5 +5x^4 -4x^3 +2x^2 +7x +3

Q(x) = -5

D(x) = x + 2

R(x) = 13

Answer 2

No, you didn't get it

First of all, your P(x) = Q(x) - D(x) + R(x)
makes no sense, should have been
P(x) = Q(x) x D(x) + R(x)

3x^5 +5x^4 -4x^3 +2x^2 +7x +3 ÷ (x+2)
......
(3x^5 +5x^4 -4x^3 +2x^2 +7x +3)
= (3x^4 - x^3 -2x^2 + 6x - 5)(x+2) + (13/x+2)

I will let you decide which expressions go with whichever ....

Answer 3

almost.
Q(x) is the quotient. It is 3x^4-x^2-2x^2+6x-5

That is,

3x^5 +5x^4 -4x^3 +2x^2 +7x +3 = (x+2)(3x^4-x^2-2x^2+6x-5)+13

Answer 4

-x^3, as in Reiny's answer. I missed my typo.

Answer 5

Ok for P(x) = Q(x) - D(x) + R(x)

do i replace the x's with the answers
like this which looks kinda weird:
P(3x^5 +5x^4 -4x^3 +2x^2 +7x +3)Q(3 x^4 - x^3 - 2 x^2 + 6 x - 5 )D(x + 2 )
R(13)

or is it supposed to be this way:

P(x) = 3x^5 +5x^4 -4x^3 +2x^2 +7x +3

Q(x) = 3 x^4 - x^3 - 2 x^2 + 6 x - 5

D(x) = x + 2

R(x) = 13

Answer 6

i meant P(x) = Q(x) x D(x) + R(x)

Answer 7

yes.