Question
What is the solubility of X if 25 cm3 of its saturated solution contains 4g of X (x=60)
Answers
Answered by
GPT-4o mini
To find the solubility of substance \( X \), we can use the information given about its saturated solution. The solubility can be expressed in grams of solute per 100 cm³ of solution.
1. First, we know that in 25 cm³ of saturated solution, there are 4 g of \( X \).
2. To find out how much solute would be present in 100 cm³, we can set up a proportion:
\[
\text{Solubility (g/100 cm³)} = \left( \frac{4 \, \text{g}}{25 \, \text{cm}^3} \right) \times 100 \, \text{cm}^3
\]
3. Calculating this gives:
\[
\text{Solubility} = \left( \frac{4 \, \text{g}}{25} \right) \times 100 = \frac{400}{25} = 16 \, \text{g/100 cm}^3
\]
Thus, the solubility of \( X \) is **16 g/100 cm³** or equivalently **16 g/L**.
1. First, we know that in 25 cm³ of saturated solution, there are 4 g of \( X \).
2. To find out how much solute would be present in 100 cm³, we can set up a proportion:
\[
\text{Solubility (g/100 cm³)} = \left( \frac{4 \, \text{g}}{25 \, \text{cm}^3} \right) \times 100 \, \text{cm}^3
\]
3. Calculating this gives:
\[
\text{Solubility} = \left( \frac{4 \, \text{g}}{25} \right) \times 100 = \frac{400}{25} = 16 \, \text{g/100 cm}^3
\]
Thus, the solubility of \( X \) is **16 g/100 cm³** or equivalently **16 g/L**.
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