Mario simplified the expression (4 z Superscript 8 Baseline) Superscript negative 3 as shown.

(4 z Superscript 8 Baseline) Superscript negative 3 = 4 z Superscript 8 times (negative 3) Baseline = 4 z Superscript negative 24 Baseline = StartFraction 4 Over z Superscript 24 Baseline EndFraction

Which statement explains Mario’s error?
He should have added the exponents instead of multiplying them.
He should have subtracted the exponents instead of multiplying them.
He should have applied the exponent –3 to 4, and not to z, to get 4 Superscript negative 3 Baseline z Superscript 8 Baseline = 4 Superscript negative 3 Baseline z Superscript 8 Baseline = StartFraction z Superscript 8 Baseline Over 64 EndFraction.
He should also have applied the exponent –3 to 4 to get 4 Superscript negative 3 Baseline z Superscript 8 Baseline times (negative 3) Baseline = 4 Superscript negative 4 Baseline z Superscript negative 24 Baseline = StartFraction 1 Over 64 z Superscript 24 EndFraction.

1 answer

Mario's error in simplifying the expression \((4 z^8)^{-3}\) is related to how he applied the negative exponent. The correct step when applying a negative exponent to a product is to apply the exponent to each factor separately.

The correct simplification of \((4 z^8)^{-3}\) is as follows:

  1. Apply the exponent \(-3\) to both the 4 and \(z^8\): \[ (4^{-3})(z^{8 \cdot -3}) = 4^{-3} z^{-24} \]

  2. This results in: \[ 4^{-3} = \frac{1}{4^3} = \frac{1}{64} \] and \(z^{-24} = \frac{1}{z^{24}}\).

  3. Combining both results gives: \[ (4 z^8)^{-3} = \frac{1}{64 z^{24}} \]

Therefore, the correct statement explaining Mario's error is: He should have applied the exponent –3 to both factors (4 and \(z^8\)) instead of just to \(z^8\), leading to \(4^{-3} z^{-24}\) instead of just \(4 z^{-24}\).

The closest option that reflects this reasoning is: He should have applied the exponent –3 to 4, and not to z, to get \(4^{-3} z^{8} = \frac{z^{8}}{64}\). This option, while slightly off in wording, captures the error in how he applied the exponent.