Question

Hooper has 4 red balls, 2 white balls, 3 back balls and 9 blue balls. Find the ball whose event of selection comes under equally likely event.
Red
White
Black
Blue

Answer 1

To determine which ball's selection comes under equally likely events, we need to consider the total number of balls and the number of each color.

- Red balls: 4
- White balls: 2
- Black balls: 3
- Blue balls: 9

Total number of balls = 4 (red) + 2 (white) + 3 (black) + 9 (blue) = 18 balls.

In the context of equally likely events, each color of ball needs to have the same probability of being selected. Since the number of balls of each color is different, the selection probabilities are not equal.

Here's a breakdown of the probabilities:
- Probability of selecting a red ball = Number of red balls / Total number of balls = 4/18
- Probability of selecting a white ball = Number of white balls / Total number of balls = 2/18
- Probability of selecting a black ball = Number of black balls / Total number of balls = 3/18
- Probability of selecting a blue ball = Number of blue balls / Total number of balls = 9/18

Since these probabilities are not equal, none of the colors represents an equally likely event.

If you meant to find which single selection is equally likely (in terms of a chance to select a ball of a specific color), that concept does not apply to this scenario because selection is based on the quantity of each color.

So, to answer your question directly: **None** of the events of selecting red, white, black, or blue balls are equally likely events.