Asked by Diggs

A 50.0 mL sample of 0.200 M AgNO3(aq) was allowed to react with an excess of NaCl(aq). The AgCl precipitate from the reaction was carefully dried and weighed. How many grams of precipitate should be obtained? I'm currently stuck and need help asap!!
Answered by DrBob222
AgNO3 + NaCl ==> AgCl + NaNO3

Here is a sample stoichiometry problem i posted. Just follow the instructions. moles AgNO3 = M x L.
http://www.jiskha.com/science/chemistry/stoichiometry.html
Answered by fs
tydt
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