40 g of Sb*(1 mole/121.76 g)= moles of Sb=0.329
80 g of O * (1 mole/16.0 g)= moles of O=5
divide lowest moles by the other
Sb=0.329/0.329=1
O=5/0.329=15
SbO15
Do not think that this is even possible to synthesize!!!!
40g of antimony combine with 80g of oxygen to form an oxide of antimony what is the simplest formula of the oxide
1 answer