Asked by caroline

A 2.9-L sample of paint that has a density of 4.65 g/mL is found to contain 26.7 g Pb3N2(s). How many grams of lead were in the paint sample?

Answers

Answered by DrBob222
You don't need the density or volume of the paint.
Convert 26.7 g Pb3N2 to mols moles = grams/molar mass.

Moles Pb must be 3x moles Pb3N2.
grams Pb = mols Pb x molar mass Pb.

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