Asked by सदानंद पांडेय
                A 3L sample of paint that has a density of 5 g/ml is found to contain 10% by mass Pb3N2(s). How many
grams of lead were in the paint sample?
            
        grams of lead were in the paint sample?
Answers
                    Answered by
            DrBob222
            
    mass = volume x density.
mass = 3000 mL x 5 g/mL = ? grams paint.
It contains 10% Pb3N2 so ?grams paint x 0.10 = grams Pb3N2.
    
mass = 3000 mL x 5 g/mL = ? grams paint.
It contains 10% Pb3N2 so ?grams paint x 0.10 = grams Pb3N2.
                    Answered by
            R_scott
            
    10% of the 15 kg of paint is Pb3N2
find the percentage (by mass) of Pb in Pb3N2
...multiply the result by 10% and by 15kg
    
find the percentage (by mass) of Pb in Pb3N2
...multiply the result by 10% and by 15kg
                    Answered by
            Olivia
            
    Sry to say bt what u wrote it is literally not understable u only know what u wrote
    
                    Answered by
            CHAMP
            
    Sidha sidha answer post ni kr skte
    
                    Answered by
            Ayush Raj
            
    1435.3g
    
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