To solve the equation \(2x^2 = 32\), follow these steps:
- Divide both sides by 2:
\[ x^2 = \frac{32}{2} \]
\[ x^2 = 16 \]
- Take the square root of both sides:
\[ x = \sqrt{16} \quad \text{or} \quad x = -\sqrt{16} \]
\[ x = 4 \quad \text{or} \quad x = -4 \]
So, the solutions for \(x\) are:
\[ x = 4 \quad \text{or} \quad x = -4 \]