A brick is thrown upward from the top of a building at an angle of 40° to the horizontal and with an initial speed of 12 m/s. If the brick is in flight for 2.5 s, how tall is the building?

Answer 1

Consider the vertical component of velocity. Vvertial=sin40 * 12

hf=ho+Vi*t-4.9 t^2
well ho is your unknown, hf=0, vi=12sin40, and you know time
solve for ho